2[2x+2(y-2)]=1

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Solution for 2[2x+2(y-2)]=1 equation:


Simplifying
2[2x + 2(y + -2)] = 1

Reorder the terms:
2[2x + 2(-2 + y)] = 1
2[2x + (-2 * 2 + y * 2)] = 1
2[2x + (-4 + 2y)] = 1

Reorder the terms:
2[-4 + 2x + 2y] = 1
[-4 * 2 + 2x * 2 + 2y * 2] = 1
[-8 + 4x + 4y] = 1

Solving
-8 + 4x + 4y = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 4x + 8 + 4y = 1 + 8

Reorder the terms:
-8 + 8 + 4x + 4y = 1 + 8

Combine like terms: -8 + 8 = 0
0 + 4x + 4y = 1 + 8
4x + 4y = 1 + 8

Combine like terms: 1 + 8 = 9
4x + 4y = 9

Add '-4y' to each side of the equation.
4x + 4y + -4y = 9 + -4y

Combine like terms: 4y + -4y = 0
4x + 0 = 9 + -4y
4x = 9 + -4y

Divide each side by '4'.
x = 2.25 + -1y

Simplifying
x = 2.25 + -1y

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